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Dividing by variable when solving algebraic equation
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RE: Dividing by variable when solving algebraic equation
(October 25, 2016 at 9:54 pm)Fireball Wrote:
(October 25, 2016 at 8:13 am)robvalue Wrote: It may have a repeated solution, however. Some quadratic equations have no real solutions, but they all have at least one complex solution.

Could I have an example?

x^2 +2x + 1 = 0 => (x+1)^2 = 0 => x = -1 (repeated solution due to the left side of the original equation being a perfect square).

To be clear, repeated solution does not apply to the specific form of quadratic equation that Vic referred to: (i.e., x^2 = constant). Aside from when the constant is 0, there will always be two solutions to such an equation.
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RE: Dividing by variable when solving algebraic equation - by Grandizer - October 25, 2016 at 10:00 pm

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