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 Dividing by variable when solving algebraic equation Alex K Ich fühle Luft von anderem Planeten Religious Views: Theism is not plausible Posts: 15940 Threads: 87 Joined: 19th January 2014 Reputation: 84 RE: Dividing by variable when solving algebraic equation 27th October 2016, 05:56 (This post was last modified: 27th October 2016, 05:57 by Alex K. ) This kind of game of wandering around the complex plane to pick up to correct solution to a complex square root or a logarithm is super important in physics, by the way. For example, there's a theorem central to scattering theory and quantum theory called the "optical theorem" which tells you that the imaginary part gives you the total scattering cross section (basically the probability of two particles doing something when they meet), and the sign of that imaginary part tells you whether causality is preserved or not, because if you got it wrong, you'd have negative scattering cross section, which would mean the probability for something scattering is negative. The original prescription how to properly deal with paths through the complex plane in particle scattering is by Feynman himself, and is called the Feynman prescription accordingly. The fool hath said in his heart, There is a God. They are corrupt, they have done abominable works, there is none that doeth good. Psalm 14, KJV revised edition robvalue Chainsaw of logic Religious Views: Order of Kittencornz Posts: 26551 Threads: 184 Joined: 9th August 2014 Reputation: 139 RE: Dividing by variable when solving algebraic equation 27th October 2016, 06:29 (This post was last modified: 27th October 2016, 06:29 by robvalue. ) Very nice description, thanks Alex I'm rusty with a lot of this stuff. I've always found complex numbers fascinating. Even though they don't map directly to the real world (you can't have i apples), you can map the real world into complex numbers, manipulate them, then extract meaningful results. I remember one instance where you introduce complex numbers to make an integration easier. I don't recall the specifics, but it was something to do with turning a trig function into the real part of a complex exponential function. I think. Like: SinA = real[SinA + iCosA] = real[e^(iA)] Feel free to send me a private message. Please visit my website here! It's got lots of information about atheism/theism and support for new atheists. Alex K Ich fühle Luft von anderem Planeten Religious Views: Theism is not plausible Posts: 15940 Threads: 87 Joined: 19th January 2014 Reputation: 84 RE: Dividing by variable when solving algebraic equation 27th October 2016, 06:48 (This post was last modified: 27th October 2016, 06:50 by Alex K. ) yup, except the i is with the Sin though and Cos is the real part as you can verify if you plug in 0 into the exponential I simply think of complex numbers as *the* way to do calculations with pairs of real numbers. The laws we use for them is basically the only way they can be if we want the usual rules of adding and multiplications to apply. I find that that makes them appear much less mysterious. One mystery is that complex numbers seem to be intricately woven into quantum physics. Quantum amplitudes and wave functions are always complex, there doesn't seem to be a way around it... The fool hath said in his heart, There is a God. They are corrupt, they have done abominable works, there is none that doeth good. Psalm 14, KJV revised edition robvalue Chainsaw of logic Religious Views: Order of Kittencornz Posts: 26551 Threads: 184 Joined: 9th August 2014 Reputation: 139 RE: Dividing by variable when solving algebraic equation 27th October 2016, 07:01 Ah yeah of course. Wow, how strange! I wish I still had the brain power to learn such complex things. Heh. Pun not intended. Feel free to send me a private message. Please visit my website here! It's got lots of information about atheism/theism and support for new atheists. mihoda Junior Member Religious Views: Atheist Posts: 47 Threads: 7 Joined: 13th September 2016 Reputation: 0 RE: Dividing by variable when solving algebraic equation 30th October 2016, 23:48 (This post was last modified: 30th October 2016, 23:51 by mihoda. ) (27th October 2016, 03:05)Alex K Wrote: 1=sqrt(1)=sqrt(-1 * -1)=sqrt(-1)*sqrt(-1)= i*i=-1 The error is in the first equality. sqrt(1) = +-1  When you later split the factors you are explicitly forcing one branch of the solution by again, reducing a choice: sqrt(-1) = +-i So in full: +-1 = sqrt(1) = sqrt(-1 * -1) = sqrt(-1) * sqrt(-1) = +-i * +-i = +-1 Grandizer Previous username: Irrational Posting Freak Religious Views: Logically speaking, God the Creator exists not. Posts: 2672 Threads: 23 Joined: 31st May 2014 Reputation: 22 RE: Dividing by variable when solving algebraic equation 30th October 2016, 23:56 (30th October 2016, 23:48)mihoda Wrote: (27th October 2016, 03:05)Alex K Wrote: 1=sqrt(1)=sqrt(-1 * -1)=sqrt(-1)*sqrt(-1)= i*i=-1 The error is in the first equality. sqrt(1) = +-1  When you later split the factors you are explicitly forcing one branch of the solution by again, reducing a choice: sqrt(-1) = +-i So in full: +-1 = sqrt(1) = sqrt(-1 * -1) = sqrt(-1) * sqrt(-1) =  +-i * +-i = +-1 Square root of a number, by convention, is always positive. Kernel Sohcahtoa The Outsider Religious Views: non-religious and non-theist Posts: 267 Threads: 15 Joined: 5th September 2016 Reputation: 16 RE: Dividing by variable when solving algebraic equation 31st October 2016, 01:06 (This post was last modified: 31st October 2016, 01:08 by Kernel Sohcahtoa. ) (27th October 2016, 06:48)Alex K Wrote: yup, except the i is with the Sin though and Cos is the real part as you can verify if you plug in 0 into the exponential I simply think of complex numbers as *the* way to do calculations with pairs of real numbers. The laws we use for them is basically the only way they can be if we want the usual rules of adding and multiplications to apply. I find that that makes them appear much less mysterious. One mystery is that complex numbers seem to be intricately woven into quantum physics. Quantum amplitudes and wave functions are always complex, there doesn't seem to be a way around it... I must say that when I learned about complex numbers from Trigonometry, 7th edition by Charles P. McKeague and Mark D. Turner, I was very fascinated with their coverage of them.  In particular, I enjoyed the following areas: trigonometric form for complex numbers; products and quotients in trigonometric form (I loved De Moivre's Theorem); roots of a complex number (this was awesome).  Hence, IMO, I found complex numbers to be quite wonderful. "I am fearful when I see people substituting fear for reason." Klaatu, from The Day The Earth Stood Still (1951) « Next Oldest | Next Newest »

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