Watching the news. Finishing off a sirloin steak.
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Current time: April 26, 2024, 12:59 am
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What's everyone up to right now?
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"For me, it is far better to grasp the Universe as it really is than to persist in delusion, however satisfying and reassuring." - Carl Sagan
Considering some tiramusu for dessert.
RE: What's everyone up to right now?
February 26, 2017 at 12:45 am
(This post was last modified: February 26, 2017 at 12:46 am by Kernel Sohcahtoa.)
I'm learning about the beauty of isomorphisms and am just finishing up reading a proof of Cayley's theorem, which states that every group is isomorphic to a group of permutations. Once I'm done, it's Star Trek time.
RE: What's everyone up to right now?
February 26, 2017 at 2:38 am
(This post was last modified: February 26, 2017 at 2:39 am by Alex K.)
(February 26, 2017 at 12:45 am)Kernel Sohcahtoa Wrote: I'm learning about the beauty of isomorphisms and am just finishing up reading a proof of Cayley's theorem, which states that every group is isomorphic to a group of permutations. Once I'm done, it's Star Trek time. I was going to reply "surely you mean every finite group!" but no, I checked and it's every group, which is intriguing. So here's my question: What's the permutation group containing the real line with plus?!
The fool hath said in his heart, There is a God. They are corrupt, they have done abominable works, there is none that doeth good.
Psalm 14, KJV revised edition
Planning my week. Considering opportunities for a hockey game and a movie.
"For me, it is far better to grasp the Universe as it really is than to persist in delusion, however satisfying and reassuring." - Carl Sagan
RE: What's everyone up to right now?
February 26, 2017 at 5:45 am
(This post was last modified: February 26, 2017 at 5:49 am by Alex K.)
(February 26, 2017 at 2:38 am)Alex K Wrote:(February 26, 2017 at 12:45 am)Kernel Sohcahtoa Wrote: I'm learning about the beauty of isomorphisms and am just finishing up reading a proof of Cayley's theorem, which states that every group is isomorphic to a group of permutations. Once I'm done, it's Star Trek time. Ah it seems my question was almost trivial. Since all bijections G->G are apparently permutations according to the relevant definitions, simply having the group action of adding a real number will already be a permutation, and so the set of bijective maps g_c: R->R, x |-> c+x for arbitrary c € R, already does the trick. It's isomorphic to R (with composition instead of + as the operation) and it is a subgroup of the bijections on R
The fool hath said in his heart, There is a God. They are corrupt, they have done abominable works, there is none that doeth good.
Psalm 14, KJV revised edition
Cold symptoms sufficiently bad that I'm leery about going out for my usual Sunday afternoon outdoor fitness activity (snowshoeing this week).
Rather than chancing it and risking a relapse, I read for a while and am now working on a sewing project. I have to go out later to get a bus pass, but otherwise will be staying close to home and letting this razzafracking cold work its way out of my system.
Looking at farmersonly.com dating website.
"For me, it is far better to grasp the Universe as it really is than to persist in delusion, however satisfying and reassuring." - Carl Sagan
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