Consider P = mv
Consider v = 0
What I was taught was this:
When v = 0,
P = m * v
P = m * 0
P = 0 [Since any number * 0 = 0]
And thus P becomes 0.
Well, I'm saying that what I was taught was wrong.
This is what I think is happening(I have broken it down to what actually is happening):
When v = 0,
P = m * v
P = m [Because 0 literally means nothing. Therefore if v were 0 then it would mean that v doesn't exist in the statement,logically.Also because when the velocity of a rolling ball becomes 0 it means that the ball carries no momentum,it doesn't mean the ball carries no mass.]
m = m [Because P=m is a meaningless statement as far as momentum is concerned.It is also a wrong statement as P is not equal to m. m is equal to m.]
I mean like, think about it, If a ball lost it's velocity the momentum becomes zero not the mass.
Now consider this:
6 = 3 * 2
6 = 3 * 0
6 = 3
3 = 3
Therefore: x * 0 = x.
Do I win cookies?
Consider v = 0
What I was taught was this:
When v = 0,
P = m * v
P = m * 0
P = 0 [Since any number * 0 = 0]
And thus P becomes 0.
Well, I'm saying that what I was taught was wrong.
This is what I think is happening(I have broken it down to what actually is happening):
When v = 0,
P = m * v
P = m [Because 0 literally means nothing. Therefore if v were 0 then it would mean that v doesn't exist in the statement,logically.Also because when the velocity of a rolling ball becomes 0 it means that the ball carries no momentum,it doesn't mean the ball carries no mass.]
m = m [Because P=m is a meaningless statement as far as momentum is concerned.It is also a wrong statement as P is not equal to m. m is equal to m.]
I mean like, think about it, If a ball lost it's velocity the momentum becomes zero not the mass.
Now consider this:
6 = 3 * 2
6 = 3 * 0
6 = 3
3 = 3
Therefore: x * 0 = x.
Do I win cookies?
