Why x*0 = x

[Tiberius]

There's also this pattern I found..

5*5 = 5+5+5+5+5+ 0
5*6 = 5+6+6+6+6+ 1
5*7 = 5+7+7+7+7+ 2

4*4 = 4+4+4+4+ 0
4*5 = 4+5+5+5+ 1
4*6 = 4+6+6+6+ 2

3*3 = 3+3+3+ 0
3*4 = 3+4+4+ 1
3*5 = 3+5+5+ 2

2*2 = 2+2+ 0
2*3 = 2+3+ 1
2*4 = 2+4+ 2

1*1 = 1+ 0
1*2 = 1+ 1
1*3 = 1+ 2

0*0 =+ 0
0*1 =+ 1
0*2 =+ 2

You mess up your own pattern at the end. Let's define the pattern using algebra:

x * y = x + ((x - 1) * y) + (y - x)

Plugging in x=5, and y=6:

5 * 6 = 5 + (4 * 6) + 1
5 * 6 = 5 + (6 + 6 + 6 + 6) + 1

Plugging in x=2, and y=4:

2 * 4 = 2 + (1 * 4) + 2
2 * 4 = 2 + 4 + 2

Seems to match your pattern, right?

Let's try x=0, y=1

0 * 1 = 0 + (-1 * 1) + 1
0 * 1 = 0 + -1 + 1
0 * 1 = 0

Tada! Math still works, the universe isn't broken. If you forget the middle part of your pattern, which is essentially "add m to itself n-1 times" then you don't get a correct answer.

By the way, your pattern simplifies to:

x * y = x + ((x - 1) * y) + (y - x)
x * y = x + (xy - y) + y - x
x * y = xy

So you can prove its the correct pattern using algebra anyway.