(March 16, 2016 at 1:29 pm)Tiberius Wrote: I basically worked it out with a table like Clueless Morgan posted above, and got the answer as 3 as well.
Hey Tiberius. Have you had a look at Rob's abortion of a probability problem, drawing names from hats? As I got close enough to appreciate what all is required, it strikes me as just a lot of brute counting and calculating with no likely elegance in the solution. Do you know the problem? If so can you say whether you think its solution is likely to warrant the effort?
