Bit flipping

[SteelCurtain]

So I am doing my final Discrete Maths project and I am having a little bit of an issue. The prof is really specific, she'll take off for unnecessary code.

I need to do the following without an if or if-else statement. I know it's possible, just need some tricky math.

I need to have one statement which basically does the following:

I have a running total, if that running total is even, then I need to keep a binary bit the same. If that running total is odd, I need to flip the bit.

The following code would work, but I need to do the same without the if-else structure:

Code:

        for (int i = 1; i < 9; i++) //loop 9 times (the gray code word is 9 bits long)
        {
         if (grayTot % 2 != 0)                                                          //if the running total is not even
                binary[i] = gray[i] * -1 + 1;                                       // flip the bit
         else                                                                                  //if the running total is even
                binary[i] = gray[i];                                                    //keep the bit
         grayTot += gray[i];                                                           // update the running total
        }

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