Hi from scared Holubice

[lilphil1989]

The posibility of you getting those numbers in a lottery are closer to 1billion : 1 Against ...about the same chances of these being the end days I am wondering.

Actually it's not possible to say. He told us we get to choose 6 numbers, but not how many numbers we get to choose from.

If we have N numbers to choose from, on the first roll the probability of getting a given chosen number is 1/N. On the second, the probability is 1/(N-1) (since there is one less ball), on the third 1/(N-2) and so on up to 1/(N-5).

compounding these probablilites: P = 1/N * 1/(N-1) * ... 1/(N-5)

or equivalently, P = (N-6)! / N! where N! = 1 * 2 * 3 * 4 * .... N

This is the probability for our numbers to come out in a given order, but it doesn't matter which order our numbers come out in. There are 6! ways to arrange 6 numbers, so our chance of winning is increased by this factor:

P = (N-6)! 6! / N!

But since we don't have N for this case, we can't determine the odds of winning.


There, I fed the troll.