RE: Mathematicians who are finitists.
July 9, 2019 at 2:54 am
(This post was last modified: July 9, 2019 at 3:50 am by A Toy Windmill.)
(July 8, 2019 at 3:38 pm)Jehanne Wrote: As p goes to infinity? Define your universe for p?p does not go anywhere. It would not even appear in the formalized theorem.
The only variables in the formalized theorem are the numerator and denominator of ε. p = f(ε) where f is the primitive recursive function which sends n to the smallest p such that 2^p > n. We could, however, just take f to be the successor function, and apply it to the numerator of ε. The proof would be fine, since 2^{m+1} >= 2^{(m + 1) / n} > n.