RE: Question for finitists -- 0.999... = 1?
November 26, 2022 at 5:17 pm
(This post was last modified: November 26, 2022 at 5:18 pm by polymath257.)
(November 26, 2022 at 12:21 pm)LinuxGal Wrote: Define:
x = 0.999...
Multiply both sides by 10
10x = 9.999...
Isolate integer part
10x = 9 + 0.999...
By definition of x
10x = 9 + x
Subtract x from both sides
9x =9
Divide both sides by 9
x = 1
Step 1: Prove the expression .999.... makes sense.
Otherwise, you could argue as follows:
x=1+2+4+8+16+...
2x=2+4+8+16+32+...
Hence,
x=1+2x
so
-x=1
x=-1
In particular,
1+2+4+8+... <0.