[split] 0.999... equals 1

[Violet]

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1. You cannot get more accurate, because you could not divide 1 evenly into three. 1/3=.3^ is an approximation based on that we cannot get any closer without overshooting one, but neither can we reach one.

If we can't get closer without overshooting, we are at the number itself. This again is the definition of different numbers.

2. 3 X 3 does = 9, and .9^ still doesn't equal one. I do not see why I would have to doubt this.

1/3 = 0.3r

What you don't understand is that 0.3r * 3 equals 0.9r, so I must assume that you do not believe 3 * 3 = 9.

3. If that is not mathematically possible, then infinity was not possible to begin with Infinity + 1 is still infinity... it is just an added one on top of the initial concept.

Infinity is a concept, one that you don't seem to understand. Infinity is not a finite number; it is limitless, it has no end. You cannot add 1 to infinity since it has no limit. 0.9r is an infinitely long number; it has no end. It is a limitless string of 9s. There is nothing you can add to it to make it equal 1 (there is no gap for anything to be put in), therefore it is already equal to 1 (as I have shown).

I do not see how you reckon that .9^ is any more valid than the .0^1 long gap .9^ requires to equal one. There are an infinite amount of zeros between that decimal and that one... just as there is an infinite amount of nines following the decimal.

An infinite amount cannot have an end. It is limitless. The concept of "an infinite amount of zeroes" followed by a 1 means there is an end to infinity, which is a contradiction.

Establishment does not make something 'right', and mathematical establishment has been proved wrong before. Some of us understand the concept of endless... and justly realize that endless .9^ by definition means that it never becomes one. If .9^ were equal to one... then .0^1 would be equal to zero. Those numbers are separated from both one and zero by a mere .0^1... but that does not mean that the .0^1 is not there.

Again, .0^1 is a logically and mathematically impossible number. You cannot have an infinite string of zeros with a 1 on the end. Infinity has no limits, ergo there is no end for the 1 to be placed on.

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They aren't the same number because there's always a gap to infinity. They cannot meet.

Evidently you don't understand the concept of infinity if you think there are gaps. Infinity is limitless.

Right - 'amount'. By their logic - I could give you 10,000 x 99p in exchange for your £10,000 and be £100 in profit. Wanna do some money exchanges?

99p is not an infinitely long number. Your example is complete nonsense, and not related to mine in any way since you do not use infinities.

Decimal numbers can't always be accurate. This proves it.

Decimal notation can write any kind of number. That is their purpose. All this proves is that you don't understand mathematical concepts like infinity.

Pi is a decimal summation so is more accurate than 22/7

You just said decimals can't always be accurate, and you use the phrase "so is more accurate", meaning you know that decimals are more accurate (why say "so" otherwise). Either you accept that decimals are always accurate and accept the proof, or reject mathematics

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So i take it, if .3^*3=.9^... and 3*3=9... then 3*3= ten? ^_^ lol ^_^

If you can't get any closer without overshooting... it means that you cannot evenly distribute the 1 into that many pieces. 3's and 4's, 6's, 7's 8's, and 9's do not perfectly go into 10... and I do not see why they should perfectly go into one either. What you do not understand is that this 'proven' math is complete nonsense.

You tied a concept into a number, I tied a concept into a number. Your .9^ is no more valid than .0^1. This number exists only because .9^ is not one until you add a number with the = # of 0's as you have nines... and then put a one following them. If you have limitless nines... you have limitless zeros. But no matter how many nines you get, you will always need that minute .0^1 to reach one. By the definition of infinite nines: your nines will never reach one.

There is no contradiction. There is a limitless amount of zeros, one zero less than the amount of nines, every digit of the way. And wherever your ever-moving last 9 in .9^ is: there is a 1 occupying the equivalent place in the 0^1. You are always adding your digits on at the end of your equation... but I am inserting my infinite zeros from the beginning.

You mock my understanding of infinity... when you keep rounding infinite nines to one ^_^ Infinite nines will infinitely never reach 1, just as infinite .3^ will infinitely never reach .34. (The point, is that the gap is NOT finite... the gap is ENDLESS! )