(October 19, 2009 at 2:51 pm)Meatball Wrote: I think it might be better to use 'there exists no number that you can add to .9r such that the result is 1' than 'there exists no number between .9r and 1'
Any of the deniers in this thread, feel free to show me a value of z that breaks this argument. If .9r is so obviously a lesser number than 1, it shouldn't be a big deal, right? So what is it?
- For every x and y, where x and y are real numbers and x < y, there exists a positive real number, z, such that x + z = y.
- There exists no real number that you can add to .9r such that the result is 1, and vice versa
- Therefore, we can conclude that .9r = 1.
For all the beans: 1 - .9r = _____
I like that Meatball. Well put.
The only reason there is no number is because the infinite card is played. What about an infinite series of 0.1... ? In the same way there can be no number between 0.1... and 1 for the same reason.. so every infinite greater than 0 = 1
0.2... = 1
0.3... = 1
0.4... = 1
etc