RE: Needing some help with Discrete
April 2, 2014 at 5:22 pm
(This post was last modified: April 2, 2014 at 5:33 pm by Alex K.)
That's right, the formula is 2^n:
8=2^3
16=2^4
2=2^(2^0)
Example:The first set contains 3 elements: a, b, {a,b}
You can form the 8 subsets
0={}
{a}
{b}
{a,b}
{{a, b}}
{a,{a,b}}
{b,{a,b}}
{a,b,{a,b}}
Note the difference betw the fourth and the fifth. Thw fourth contains two elements, a and b, the fifth set contains one element, which by coincidence is the fourth set itself again to confuse you.
8=2^3
16=2^4
2=2^(2^0)
Example:The first set contains 3 elements: a, b, {a,b}
You can form the 8 subsets
0={}
{a}
{b}
{a,b}
{{a, b}}
{a,{a,b}}
{b,{a,b}}
{a,b,{a,b}}
Note the difference betw the fourth and the fifth. Thw fourth contains two elements, a and b, the fifth set contains one element, which by coincidence is the fourth set itself again to confuse you.
The fool hath said in his heart, There is a God. They are corrupt, they have done abominable works, there is none that doeth good.
Psalm 14, KJV revised edition
