RE: Thinking about infinity
April 29, 2016 at 3:59 am
(This post was last modified: April 29, 2016 at 4:04 am by robvalue.)
Just as an aside:
When we use the concept of infinity in mathematics, it is usually employed as a limit. We allow a number to tend towards infinity, and we see what effect that has.
For example, 1/n tends towards zero as n tends towards infinity.
The technical way of writing this is:
For any positive number k, we can find a number m so that 1/n < k for all n >= m (greater than or equal to)
[In general we would use |1/n| which means to ignore any negative values, but we know in this case, dealing with positive values of n, 1/n is always positive anyway.]
In other words, however small we want the value of 1/n to be, we can find a point so that the values of 1/n that follow are all below that number. It gets arbitrarily close to zero, and so we say that it becomes zero as the limit is taken of n=> infinity.
It's important that all values of 1/n are below this value of k after this point we find, or else we might be dealing with an oscillating function that jumps in and out of the required zone.
This value of m can be easily found:
We want 1/n < k
Multiply by n to give 1 < nk
Divide by k to give 1/k < n
Turning that around gives n > 1/k
So the value of m will be the first whole number greater than 1/k. Let's say k = 0.000001 (a millionth). Then we need
n > 1/0.000001
n > 1,000,000
So 1/n < 0.000001 for all n >= 1,000,001
Did that make any sense to those not familiar with the subject?
When we use the concept of infinity in mathematics, it is usually employed as a limit. We allow a number to tend towards infinity, and we see what effect that has.
For example, 1/n tends towards zero as n tends towards infinity.
The technical way of writing this is:
For any positive number k, we can find a number m so that 1/n < k for all n >= m (greater than or equal to)
[In general we would use |1/n| which means to ignore any negative values, but we know in this case, dealing with positive values of n, 1/n is always positive anyway.]
In other words, however small we want the value of 1/n to be, we can find a point so that the values of 1/n that follow are all below that number. It gets arbitrarily close to zero, and so we say that it becomes zero as the limit is taken of n=> infinity.
It's important that all values of 1/n are below this value of k after this point we find, or else we might be dealing with an oscillating function that jumps in and out of the required zone.
This value of m can be easily found:
We want 1/n < k
Multiply by n to give 1 < nk
Divide by k to give 1/k < n
Turning that around gives n > 1/k
So the value of m will be the first whole number greater than 1/k. Let's say k = 0.000001 (a millionth). Then we need
n > 1/0.000001
n > 1,000,000
So 1/n < 0.000001 for all n >= 1,000,001
Did that make any sense to those not familiar with the subject?
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Index of useful threads and discussions
Index of my best videos
Quickstart guide to the forum