| 
		
	
	
	
		
	Posts: 92 
	Threads: 14 
	Joined: April 2, 2012
	
 Reputation: 
2 
	
		
		
		Needing some help with Discrete April 2, 2014 at 4:05 pm 
		Currently studying for a test and noticed this problem 
 
 2.1.23. How many elements does each of these sets have where a and b are distinct elements?
 
 A.  P({a, b, {a, b}})
 B.  P({∅, a, {a}, {{a}}})
 C.  P(P(∅))
 
 For whatever reason this was not covered in class (It's not in my notes and i take notes in that class religiously) Was wondering if anyone knew how the hell do this, the book we were assigned does a poor job of explaining it, or anything for that matter.
 
		
	 
	
	
	
		
	Posts: 69247 
	Threads: 3759 
	Joined: August 2, 2009
	
 Reputation: 
258 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 4:20 pm 
		
	 
	
	
	
		
	Posts: 18544 
	Threads: 131 
	Joined: January 19, 2014
	
 Reputation: 
90 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 5:07 pm 
(This post was last modified: April 2, 2014 at 5:18 pm by Alex K.) 
		Is P being defined as the set of subsets including the empty set 0 and the set itself? 
Then P(0)= {0}
 
and P(P(0))={0,{0}}
 
You can take it from here    
P.s. I think if a set S has n elements, P(S) always has 2^n, because each can be in a subset or not.
	
The fool hath said in his heart, There is a God. They are corrupt, they have done abominable works, there is none that doeth good.
Psalm 14, KJV revised edition 
		
	 
	
	
	
		
	Posts: 92 
	Threads: 14 
	Joined: April 2, 2012
	
 Reputation: 
2 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 5:10 pm 
		 (April 2, 2014 at 5:07 pm)Alex K Wrote:  Is P being defined as the set of subsets including the empty set and the set itself? 
I've no clue, that's literally it says..
	 
		
	 
	
	
	
		
	Posts: 18503 
	Threads: 79 
	Joined: May 29, 2010
	
 Reputation: 
125 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 5:15 pm 
		The empty set is.
	 
		
	 
	
	
	
		
	Posts: 1246 
	Threads: 14 
	Joined: January 5, 2014
	
 Reputation: 
9 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 5:16 pm 
		 (April 2, 2014 at 5:07 pm)Alex K Wrote:  Is P being defined as the set of subsets including the empty set 0 and the set itself?
 Then P(0)= {0}
 
 and P(P(0))={0,{0}}
 
 You can take it from here
  
What u will end up getting is opp.... yeah u know me...good song yo!!!
	 
		
	 
	
	
	
		
	Posts: 32298 
	Threads: 120 
	Joined: February 22, 2011
	
 Reputation: 
159 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 5:16 pm 
(This post was last modified: April 2, 2014 at 5:17 pm by Angrboda.) 
		 (April 2, 2014 at 4:05 pm)SavageNerdz Wrote:  Currently studying for a test and noticed this problem 
 
 2.1.23. How many elements does each of these sets have where a and b are distinct elements?
 
 A.  P({a, b, {a, b}})
 B.  P({∅, a, {a}, {{a}}})
 C.  P(P(∅))
 
 For whatever reason this was not covered in class (It's not in my notes and i take notes in that class religiously) Was wondering if anyone knew how the hell do this, the book we were assigned does a poor job of explaining it, or anything for that matter.
 Wikipedia Wrote:Writing A = {1, 2, 3, 4 } means that the elements of the set A are the numbers 1, 2, 3 and 4. Sets of elements of A, for example {1, 2}, are subsets of A.
 Sets can themselves be elements. For example consider the set B = {1, 2, {3, 4}}. The elements of B are not 1, 2, 3, and 4. Rather, there are only three elements of B, namely the numbers 1 and 2, and the set {3, 4}.
 
 The elements of a set can be anything. For example, C = { red, green, blue }, is the set whose elements are the colors red, green and blue.
 
   A.  P({a, b, {a, b}}) 
    B.  P({∅, a, {a}, {{a}}}) 
    C.  P(P(∅))
 
It's been too long, so don't take my word for it, but...
 
A. one element (the set {a,b,{a,b}}), or three, depending. 
B. one element or four, again depending. 
C. Not sure.  I don't know if the empty set counts as an element; my guess would be, yes, it does.
	 
		
	 
	
	
	
		
	Posts: 18544 
	Threads: 131 
	Joined: January 19, 2014
	
 Reputation: 
90 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 5:19 pm 
		rasetsu, I think you gotta go 1 level deeper, inside the first bracket.
	 
The fool hath said in his heart, There is a God. They are corrupt, they have done abominable works, there is none that doeth good.
Psalm 14, KJV revised edition 
		
	 
	
	
	
		
	Posts: 92 
	Threads: 14 
	Joined: April 2, 2012
	
 Reputation: 
2 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 5:20 pm 
		The back of the book says this is the answers:
 A: 8
 B: 16
 C: 2
 
 Which is why i'm so confused, it is completely blowing my mind right about now..
 
		
	 
	
	
	
		
	Posts: 18544 
	Threads: 131 
	Joined: January 19, 2014
	
 Reputation: 
90 
	
		
		
		RE: Needing some help with Discrete April 2, 2014 at 5:22 pm 
(This post was last modified: April 2, 2014 at 5:33 pm by Alex K.) 
		That's right, the formula is 2^n:
 8=2^3
 16=2^4
 2=2^(2^0)
 
 Example:The first set contains 3 elements: a, b, {a,b}
 
 You can form the 8 subsets
 0={}
 {a}
 {b}
 {a,b}
 {{a, b}}
 {a,{a,b}}
 {b,{a,b}}
 {a,b,{a,b}}
 
 Note the difference betw the fourth and the fifth. Thw fourth contains two elements, a and b, the fifth set contains one element, which by coincidence  is the fourth set itself again to confuse you.
 
The fool hath said in his heart, There is a God. They are corrupt, they have done abominable works, there is none that doeth good.
Psalm 14, KJV revised edition 
		
	 |