Unfair Coin Flip

[ErGingerbreadMandude]

Ohh so that's the problem.

In that case, I want to show an example.

So you make 12 coin toss. You get 3 heads and 9 tails. So your question is how can we make this fair as in instead of getting 3 heads and 9 tails how can we get 6 heads and 6 tails.

Isn't that a bit easy then?

I made 12 tosses so first I divide it by 2. Now I have 6.

Then I do two subtract operation: 6-3=3 and 6-9=-3

So that means I have to flip 3 tails to heads because there is less heads so that becomes 3+3=6 heads or I can flip 3 tails to heads because there is more tails so that becomes 9-3=6 tails.

So now I have 50% heads and 50% tails...