RE: Studying Mathematics Thread
April 5, 2018 at 9:01 am
(This post was last modified: April 5, 2018 at 9:02 am by polymath257.)
(April 5, 2018 at 8:48 am)robvalue Wrote:(April 5, 2018 at 7:41 am)polymath257 Wrote: OK, now try
(1^2 + 2^2 + 3^2 +...+n^2)/n^3
and
(1^3 + 2^3 + 3^3 +...+n^3 )/n^4.
Any guesses for a generalization?
After some scrawling and trying to remember old methods, I got
Sum(n^2) = (n/6)(2n^2 + 3n + 1)
Giving limit when divided by n^3 as 1/3.
If I have the energy I'll do n^4 later, but I guess it might be 1/4!
Good guess (assuming that isn't 4 factorial)! Now the challenge: prove it.
Hint: Riemann