The Monty Hall problem.

[Darwinian]

I'm not a big fan of statistics but visually in my head I get it.

The way I understand it is that the two doors you don't pick become a unit, so even if you know one of them has the goat, as a unit, there is still a 66% chance switching gives you the car because there was a 66% chance the goat was in one of the other two doors when you picked your door. And by revealing which of the two doors has the goat, there's still a 66% chance because there was always going to be a goat in one of those doors.

Am I understanding this correctly?

Yes, there's a 66.6..% chance that the car is in one of the two doors you didn't choose. Even when Monty gets rid of one of the doors the remaining door still has that 66.6..% chance.

It's a bit like being able to choose two of the doors instead of just the one.