RE: Dividing by zero
October 1, 2013 at 4:57 pm
(This post was last modified: October 1, 2013 at 5:02 pm by Simsim.)
(October 1, 2013 at 12:20 pm)little_monkey Wrote:(September 30, 2013 at 6:17 am)Simsim Wrote: So: x*(x+1)/x = (x+1), then when x approaches zero (x+1) approaches 1
That's totally wrong.
x*(x+1)/x approaches 1, if and only if x is NOT zero. At x=0, that algebraic fraction is infinite.
Sorry, have you read what you quoted for me??
I didn't say that x can be 0
Again:
(September 30, 2013 at 6:17 am)Simsim Wrote: So: x*(x+1)/x = (x+1), then when x approaches zero (x+1) approaches 1
And your expression is wrong.

"" x*(x+1)/x approaches 1, if and only if x is NOT zero. At x=0, that algebraic fraction is infinite. ""
Wrong ! That means that whatever the value of x is, the value of the fraction approaches 1 as long as x doesn't equal zero ! That's obviously wrong !
And when x=0 the algebraic fraction will not be infinite as you said. It will be "undefined".
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