Another challenge.

[LastPoet]

---

can u guys shoot a hole in it ??




Religion disproven by mathematics, boolean algebra,


Not (negation), denoted ¬x (sometimes NOT x, Nx or !x), satisfies ¬x = 0 if x = 1 and ¬x = 1 if x = 0.
And (conjunction), denoted x?y (sometimes x AND y or Kxy), satisfies x?y = 1 if x = y = 1 and x?y = 0 otherwise.


first we must make some definitions :



The pillars of religion are the believe in the fight beween good and evil, god vs satan.

so the belief in god and satan is religion.


R = god AND satan.

and

Religion True if Atheism False
Atheism False if Religion True

To be able to use that proposition in boolean algebra we must convert this in symbols used in boolean algebra, true and false, binary notation 1 and 0.


however,satan isnt equal to god they are inverse, opposite states.


god is good, satan evil.
god has no creator, satan is created.
god lives in heaven, satan in hell.


god is 1

satan is 0


so


god is (NOT satan) is True 1 is (NOT 0) (1)

satan is (NOT god) is True 0 is (NOT 1) (0)



and

Religion is NOT Atheism True
Atheism is NOT Religion True

or

Religion is Atheism False
Atheism is Religion False


now, to substitue this in the definition of religion by boolean algebra :
And (conjunction), denoted x?y (sometimes x AND y or Kxy), satisfies x?y = 1 if x = y = 1 and x?y = 0 otherwise.
Not (negation), denoted ¬x (sometimes NOT x, Nx or !x), satisfies ¬x = 0 if x = 1 and ¬x = 1 if x = 0.

Religion is god and satan.



R = god AND (NOT god) ..... 1 AND NOT 1 = False (o)

testing it the other way

R = (NOT god) AND satan ..... NOT 1 AND 1 = False (0)


the first state and the last state of the boolean function are not possible becouse of the definition of god and satan.


So Religion is proven False.

therefore Atheism TRUE.

---

Cool story bro. Can YOU present a sollution to the problem in the OP?