Did Hubble can it wrong?

[little_monkey]

You're using this formula wrongly. In that link, they are talking about a light emanating from inside a star with a radius less than a Schwarzchild radius, which is the radius of a black hole. The point the author is making is in that case, light won't be able to escape. My thought experiment is not about light emanating from the inside of the earth, but from an emitter standing at a distance d above the ground. Different experiments require that you use the math properly.

I am using the equation correctly.

and R^* the distance between the center of mass of the gravitating body and the point at which the photon is emitted. The redshift is not defined for photons emitted inside the Schwarzschild radius, the distance from the body where the escape velocity is greater than the speed of light. Therefore this formula only applies when R^* is at least as large as r_s.

Read it again: The redshift is not defined for photons emitted inside the Schwarzschild radius, later on in the same paragraph, "When the photon is emitted at a distance equal to the Schwarzschild radius, the redshift will be infinitely large. When the photon is emitted at an infinitely large distance, there is no redshift." The author is specifically talking about a black hole.

Sorry but if you can't do the math, you're not in a position to criticize.

Oh, I can do the math. I don't want to waste my time doing so when I can't point out that your claim is wrong through a thought experiments.

So far you have shown that you can't read your own link properly, and you still can't do the math. My derivations is over 10 steps, and they are elementary. You have no excuses. You want to see the kind of math I'm capable of. See my other blogs. Here's a sample:

On GENERAL RELATIVITY:
http://soi.blogspot.ca/2014/01/the-essen...ivity.html

On QUANTUM FIELD THEORY:
http://soi.blogspot.ca/2014/04/the-essen...heory.html

On QFT IN CURVED SPACETIME:
http://soi.blogspot.ca/2014/06/quantum-f...-time.html

That's why I put 3 different emitters at 3 different distances. But I show that for all these cases, you get one general equation.

The wavelength shift of your 3 emitters would be the same when they're light years away.

You're speculating without proof. Show me with hard equations derived from fundamental principles, not just spurting an unfounded opinion.

That is not possible for a gravitational potential. It's inversely proportional with distance. So at equal distance, the gravitational potential has to be the same.

Your forgetting about the mass of the object. Gravitational potential = GM/r.

I haven't forgotten. The equations shows that it depends only on the mass of the source, which is

10) d = H Δv,

where H = (cR2source)/ (GMsource)