Our server costs ~$56 per month to run. Please consider donating or becoming a Patron to help keep the site running. Help us gain new members by following us on Twitter and liking our page on Facebook!
Current time: December 21, 2024, 11:15 pm

Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
Question for finitists -- 0.999... = 1?
#1
Question for finitists -- 0.999... = 1?
And, ultra-finitists, too!



Reply
#2
RE: Question for finitists -- 0.999... = 1?
At work.

Oh...... 'Maths'....

*Brain fritz*
Reply
#3
RE: Question for finitists -- 0.999... = 1?
I once had a real, professional mathematician corner me at a party and spend 20 minutes explaining to me why the interval from 0 to 1 is not the same as the interval from 1 to 2.

Because of the resultant trauma, I am unable to watch that video.

Boru
‘I can’t be having with this.’ - Esmeralda Weatherwax
Reply
#4
RE: Question for finitists -- 0.999... = 1?
0.000 ... 001 = 0

1 / ∞
"The first principle is that you must not fool yourself — and you are the easiest person to fool." - Richard P. Feynman
Reply
#5
RE: Question for finitists -- 0.999... = 1?
0.999=0.999
1=1
Reply
#6
RE: Question for finitists -- 0.999... = 1?
Define:

x = 0.999...

Multiply both sides by 10

10x = 9.999...

Isolate integer part

10x = 9 + 0.999...

By definition of x

10x = 9 + x

Subtract x from both sides

9x =9

Divide both sides by 9

x = 1
Reply
#7
RE: Question for finitists -- 0.999... = 1?
(November 26, 2022 at 12:21 pm)LinuxGal Wrote: Define:

x = 0.999...

Multiply both sides by 10

10x = 9.999...

Isolate integer part

10x = 9 + 0.999...

By definition of x

10x = 9 + x

Subtract x from both sides

9x =9

Divide both sides by 9

x =  1

Step 1: Prove the expression .999.... makes sense.

Otherwise, you could argue as follows:

x=1+2+4+8+16+...

2x=2+4+8+16+32+...

Hence,

x=1+2x

so

-x=1

x=-1

In particular,

1+2+4+8+... <0.
Reply
#8
RE: Question for finitists -- 0.999... = 1?
(November 26, 2022 at 5:17 pm)polymath257 Wrote: Step 1: Prove the expression .999.... makes sense.

Otherwise, you could argue as follows:

x=1+2+4+8+16+...

2x=2+4+8+16+32+...

Hence,

x=1+2x

so

-x=1

x=-1

In particular,

1+2+4+8+... <0.

Not so, since x = 0.999... has an upper bound as the decimal expansion continues without limit, but x = 1+2+4... diverges.
Reply
#9
RE: Question for finitists -- 0.999... = 1?
(November 26, 2022 at 5:54 pm)LinuxGal Wrote: Not so, since x = 0.999... has an upper bound as the decimal expansion continues without limit, but x = 1+2+4... diverges.

True.  In your case, though, you are performing the same trick - it is just that the additional digit you shifted in is an infinitesimal instead of a large value.

I'm not sure if your proof is valid, but of course one can get as close to correct as you like.
Reply
#10
RE: Question for finitists -- 0.999... = 1?
Warning: the following post contains a contiguous slice that is a PART of a larger post:
(November 26, 2022 at 6:04 pm)HappySkeptic Wrote: I'm not sure if your proof is valid...
It was valid in discrete math class when I was in University.
Reply



Possibly Related Threads...
Thread Author Replies Views Last Post
  Mathematicians who are finitists. Jehanne 99 15905 July 11, 2019 at 1:53 pm
Last Post: A Toy Windmill
  Maths proves 1=0.999.. thus ends in self contradiction shakuntala 11 6485 December 21, 2014 at 3:57 pm
Last Post: Thumpalumpacus
  If 0.999(etc) = 1, does 1 - 0.999 go to zero? Euler 26 10096 April 30, 2013 at 12:17 pm
Last Post: Mister Agenda
  [split] 0.999... equals 1 Rhizomorph13 330 114919 February 20, 2013 at 6:47 am
Last Post: Categories+Sheaves
  If 0.999 (etc.) = 1, does 1 - 0.999 = 0? Child of Stardust 16 11622 March 6, 2012 at 2:12 pm
Last Post: Child of Stardust



Users browsing this thread: 1 Guest(s)