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Current time: January 23, 2025, 3:21 am

Poll: Would you switch(and why)?
This poll is closed.
Yes
81.82%
9 81.82%
No
9.09%
1 9.09%
I don't know.
9.09%
1 9.09%
Total 11 vote(s) 100%
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The role of probability in solving the Monty Hall problem
#34
RE: The role of probability in solving the Monty Hall problem
(March 9, 2016 at 12:06 am)Jenny A Wrote:
(March 8, 2016 at 11:28 pm)Excited Penguin Wrote: Then the choice has been 50/50 all along, and it doesn't change in the least. You're just either in on it or not, that's all that changes. The chances of you being right, however, are the same throughout.

At the start of the game, running the original experiment, from your perspective you have a 1/3 chance of getting right. From the moderators' perspective and the one that is actually right since he has all the information you have a 50/50 chance. So this is not so much a puzzle as it is a trick. No mystery whatsoever here, the chances stay the same from the beginning, only your understanding of them improves, not so the actual chances.
Wrong.  Monty is required to show you a goat you didn't choose. Those are the rules. 
I never said otherwise and don't understand how this answers my argument. Who are you arguing with here?

Quote:At the start of the game one of two things will happen.  One,  you will choose the winning door.  There is a one third chance of that happening.  In that case Monty will show you one of the goats because that is all he can show you. If you switch you will get the other goat and lose.  But chances are two out of three that you will choose a goat to begin with and  then Monty must show you the other goat because those are the rules.  In that case, if you switch, the other door is the prize. So, if you switch you win two out of three times.
Ok, this obfuscatory way of putting it doesn't get you an additional third viable option, which you don't have, since he is going to eliminate one regardless of the choice you make first. You're still going to end up with only two options no matter what you do. The one you already chose and the one left after he revealed the third one. None of this switching and revealing business tells you which one of the two is more likely to hold the desired prize. You can only argue this inane point so long before you realise how wrong you are. I'm hoping the same thing will happen here.

Quote:If you don't switch,  your chances remain one in three because that is your chance of picking correctly in the first place.
You can switch or not switch all you like. There are still only two doors to choose from, not three. It is paramount that no matter how much you change the version of the game the moderator always eliminate all but an option from the ones you didn't choose after you make your initial choice. This makes it so that there will always be only two options left. Therefore 50/50, not 66/33.
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Messages In This Thread
RE: Probability? - by TheRealJoeFish - March 8, 2016 at 7:53 pm
RE: Probability? - by Excited Penguin - March 8, 2016 at 7:56 pm
RE: Probability? - by TheRealJoeFish - March 8, 2016 at 8:06 pm
RE: The role of probability in solving the Monty Hall problem - by Excited Penguin - March 9, 2016 at 12:13 am

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