RE: The role of probability in solving the Monty Hall problem
March 13, 2016 at 10:51 am
(This post was last modified: March 13, 2016 at 10:52 am by Mr.wizard.)
(March 13, 2016 at 10:39 am)IATIA Wrote: I would keep the initial door I picked. Though my chances of being correct have changed from 1 in 3 to 50/50, it will not change what is behind the door that I chose. By opening door #3 and showing me a goat, it affirms the possibility that I chose the right door, but gives me no reason to assume that I chose incorrectly (or correctly).
Game-wise however, I would assume that I had picked the right door as they would rather I chose the goat and will try to get me to change my mind.
The probability does not become 50/50 right after one goat is open, its's still 33%. Think of 100 doors, you pick 1 and the host opens 98 doors revealing goats, the probability you choose correctly initially does not become 50/50, it is still based on 1/100, because the host knows where the car is and he is going to open only goats.