(August 12, 2009 at 5:35 am)theVOID Wrote: Great video.I am. Thanks for the kind words
You the Adrian from Athiest Blogger?
If so, your blog rocks.
(August 12, 2009 at 5:45 am)theVOID Wrote: About that birthday thing:It's known as the "Birthday paradox", but the math is quite simple. It's easier to do in reverse. Suppose that we wanted to calculate the chances that 2 people did not have the same birthday.
365 days in the year
30 people in the class
1/2 chance of 2 people sharing a birthday?
I can't figure that one out.
If you have one person in the room, they have a 365/365 chance of not sharing a birthday (since there are no others in the room). If you add another person, they have 364/365 chance of not sharing a birthday (since there are only 364 days left that are not already taken.
If you have 30 people in the room, the calculation looks like this:
365/365 * 364/365 * 363/365 * 362/365 * 361/365 * 360/365 * 359/365 * 358/365 * 357/365 * 356/365 * 355/365 * 354/365 * 353/365 * 352/365 * 351/365 * 350/365 * 349/365 * 348/365 * 347/365 * 346/365 * 345/365 * 344/365 * 343/365 * 342/365 * 341/365 * 340/365 * 339/365 * 338/365 * 337/365 * 336/365
So the probability of 2 people *not* having a common birthday out of 30 people is 0.293683757.
To get the probability of 2 people having a common birthday, you simply need to subtract our result from 1:
1 - 0.293683757 = 0.706316243
So in a room of 30 people, you have a 70.6% chance of finding 2 people with the same birthday.
Q.E.D.
You can read about the problem here: http://en.wikipedia.org/wiki/Birthday_problem