The 12 Coins Puzzle

[theVOID]

Woah, i was just waiting for you to shut me down on scenario 2! I'm surprised 1 was wrong, but i'm stoned so i sorta fleshed it out as i thought about it, but i just had a bong, feeling like more math, strangely

12 Coins

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 , 12


*weigh 1234 and 5678*

Part A

If '1,2,3,4' = '5,6,7,8'
then '9,10,11,12' = Anomaly

*weigh ''7,8,9,10' and '12,11,1,2'*

if '7,8,9,10' > '12,11,1,2'
then '9,10' = Anomaly

*weigh 9,8*
if 9 = 8
then 8= anomaly

if 9 > 8
then 9 = anomaly



Part B

*weigh 1234 and 5678*

If '1,2,3,4' = '5,6,7,8'
then '9,10,11,12' = Anomaly

Set aside '7,8'

*weigh '1,9,10' and '2'11'12'

i)

if '1,9,10' = '1,11,12'
'7,8' = anomaly

*weigh '1,7' and '2,8'*

if '1,7' > 2,8'
then 7 = anomaly

ii)

If 1,9,10 > '1,11,12
then '9,10' = anomaly

*weigh '1,9,' and '2,10'*

if '1,9' > '2,10'
then 9 = anomaly

correct?