Relativistic rocket equation question thingy

[Sejanus]

Deceptively simple...

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If there's anything you can't understand, I can take a better photo...

edit: bear in mind that ln = log_e

Nice job! you did it slightly different than I did, but we still used roughly the same process.

You can do it in a few lines if you solve for delta v, then just use the identity a^b = e^(ln(a^b)) = e^(b*ln(a))

b = 2u/c and a = m0/m1

All these types of problems can generally be solved with the identities ln(a*b) = ln(a) + ln(b) and ln(a^b) = b*ln(a)

What you're describing here seems to be roughly the same as what I did, and it takes more than "a few lines". If you mean something other than I understand, please post a picture of your solution.