RE: Number crunching curios
December 21, 2013 at 6:48 am
(This post was last modified: December 21, 2013 at 7:07 am by Sejanus.)
cos(pi/2^n) gives a nested surd of the form ((2 + (2 + (2...)^1/2)^1/2)^1/2)/2 where you get n - 1 nested square roots in the numerator. I thought it was cool 
This is somewhat unrelated, but I love the elegance of multiplying by an integrating factor, e^({ p(x)dx) to make the integration of differential equations of the form dy/dx + p(x)y = q(x) (where p(x) and q(x) are understood to be functions of x) a breeze. By the way, I used the squiggly bracket { above to represent the integral sign.
This is somewhat unrelated, but I love the elegance of multiplying by an integrating factor, e^({ p(x)dx) to make the integration of differential equations of the form dy/dx + p(x)y = q(x) (where p(x) and q(x) are understood to be functions of x) a breeze. By the way, I used the squiggly bracket { above to represent the integral sign.
