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The role of probability in solving the Monty Hall problem
#71
RE: The role of probability in solving the Monty Hall problem
Let me elaborate further rob.
I'm the host.
I have 3 doors in front of you.
Now choose one to open.
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#72
RE: The role of probability in solving the Monty Hall problem
Oh wait.

Ok, I pick door 1.
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#73
RE: The role of probability in solving the Monty Hall problem
(March 13, 2016 at 8:12 am)robvalue Wrote: Oh wait.

Ok, I pick door 1.

So now I open door 3 for you.
You see a goat, I ask you if you want to change your option.

What do you do, why?
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#74
RE: The role of probability in solving the Monty Hall problem
I change door.

For all the reasons we've explained. Where is the lying coming in?
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#75
RE: The role of probability in solving the Monty Hall problem
(March 13, 2016 at 8:16 am)robvalue Wrote: I change door.

For all the reasons we've explained. Where is the lying coming in?

For the reasons you've explained?
Would you agree that changing your option works in your favor than the other way around?
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#76
RE: The role of probability in solving the Monty Hall problem
Er... what?

I don't understand you. Yes, this whole thread has been explaining why you change.

The only assumption I make is that the prize has initially been selected randomly to be behind one of the doors.

If I chose wrong initially, with 2/3 chance, I will guarantee to win if I change.

If I chose right initially, with 1/3 chance, I will lose.

Chances I win = (2/3) * 1 + (1/3) * 0 = 2/3

It's how you calculate the mean of a probability distribution.

Sum(i=1..n)[i*Prob(X=i)]
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#77
RE: The role of probability in solving the Monty Hall problem
(March 13, 2016 at 8:19 am)robvalue Wrote: Er... what?

I don't understand you. Yes, this whole thread has been explaining why you change.

The only assumption I make is that the prize has initially been selected randomly to be behind one of the doors.

If I chose wrong initially, with 2/3 chance, I will guarantee to win if I change.

If I chose right initially, with 1/3 chance, I will lose.

Chances I win = (2/3) * 1 + (1/3) * 0 = 2/3

It's how you calculate the mean of a probability distribution.

The math is all very fascinating rob, too bad you'll be returning home with a goat. The car was behind door 1.
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#78
RE: The role of probability in solving the Monty Hall problem
OK. How's the program coming? Why are you scared to run it if you're so sure you're right?

Where does the lying come in?
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#79
RE: The role of probability in solving the Monty Hall problem
(March 13, 2016 at 8:23 am)robvalue Wrote: OK. How's the program coming? Why are you scared to run it if you're so sure you're right?

Where does the lying come in?

Look back in the thread you'll see Jenny mentioning it.
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#80
RE: The role of probability in solving the Monty Hall problem
Er... OK. I don't know where to look, I'll look later.

You're meant to open the door to show me if I win or not, I don't just take your word. You know that, right?

You should go study probability distributions. If you don't understand them, you won't understand this. Although this is a very simple example of one.
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