RE: Can you cut a cake fairly to solve this middle school math problem?
August 6, 2017 at 7:34 pm
(This post was last modified: August 6, 2017 at 7:36 pm by Whateverist.)
Just as the area of the square representing the base of the cake alone must be divided into five equal pieces so long as the cuts are made from the center to five equally spaced points along the perimeter, so must the larger square consisting of the cake plus frosting. Since the portions contained inside the square representing the unfrosted cake's base are equal, if you subtract them from each piece of the larger square representing the cake plus frosting, the remaining area (representing the base area of the frosted region alone) must also be equal. Therefore the frosting is also divided equally in this solution, including the fours corner regions.
To see this I made a drawing to show directly that the base area of the frosted regions would still be equal when the frosting is applied to a thickness half the side length of the cake alone. A larger scale version of the photo and an explanation of the drawing are below.
Larger scale photo:
Explanation of the drawing:
Notice that though the yellow and red pieces get only half a corner of frosting, each one gets portion of frosting that extends into the area directly above its neighbor.
To see this I made a drawing to show directly that the base area of the frosted regions would still be equal when the frosting is applied to a thickness half the side length of the cake alone. A larger scale version of the photo and an explanation of the drawing are below.
Larger scale photo:
Explanation of the drawing:
(August 6, 2017 at 7:02 pm)popeyespappy Wrote: Green, blue and purple gets a whole corner each. Red and yellow have to share one.
Notice that though the yellow and red pieces get only half a corner of frosting, each one gets portion of frosting that extends into the area directly above its neighbor.