(July 24, 2019 at 12:09 pm)Anomalocaris Wrote:(July 24, 2019 at 11:05 am)Drich Wrote: because they do not drill deep enough.
Right, it has nothing to do with the limited heat capacity of the rocks the water might come into contact with, so the rocks cool and lose ability to generate more steam after water has been circulating through them; nor the limited thermal conductivity of the rocks, so once the rock is cooled, it takes awfully long time for new thermal energy to conduct in and heat the rocks back up again; nor the fact that porosity and water permeability of rocks decrease with depth, so at certain depth water can no longer be forced through rocks regardless of pressure.
It's because they didn't drill deep enough.
Do you bottle your farts and smell them throughout the day for inspiration?
why your analisis fails:
you assume the hole size is limited to the size hole drilled in russia and you assume like with russia the water being used is pre chilled. (which again flashed at 7.5 miles/IE they could not make the hole cooler with chilled water even after months of pumping, because by the time it got to the drill it was vapor.)
Even so if we used a water mix or a coolant like sodium glycol the coolant mixture under pressure, would flash at a much higher temp. this would reduce the energy taken from the geothermal mass. all of these things together mitigate heat loss. All one need do is calculate the thermal conductivity of the rock at 7.5 miles down below them in their part of the world and do a simple k-factor equation to determine heat loss in this process using a coolant designed to retain heat verse just water and calculate out how big the hole or a reservoir need be at the bottom of the hole to have continuous power supply. Then simply never exceed the extraction of heat beyond what the earth can replenish.. If more power is needed then don't turn the generator up, drill another hole!
Thermal conductivity (k-factor) is the measure of a material's ability to transfer heat. Materials that transfer heat readily have high k-factors, like steel (228 Btu-in/hr-ft2-°F @ 75°F mean temperature), and are classified as conductors.
[/url]calculation of k-factor and r-value - K-Flex USA
www.kflexusa.com/.../TS13%20Calculating%20Kfactor%20R%20Value%201010.pdf
[url=http://www.kflexusa.com/spaw2/uploads/files/TS13%20Calculating%20Kfactor%20R%20Value%201010.pdf]