Why God doesn't stop satan?

[R00tKiT]

The question at issue is whether P1 AND not-P1 are BOTH consistent with P2 and P3.  They cannot be consistent with both, therefore P1 is necessarily true.  If P1 is necessarily true, then she necessarily chose flavor F and her choice was not free.  Any choice that is necessarily the case is not a free one.   Since both P1 and not-P1 cannot both be consistent with P2/P3, her choice was not free, P1 is not sufficient for free will, and free will is inconsistent with them.

Okay this may get messy. Let's take it one at a time. As I suspected, you're not in disagreement with me that P2 and P3 are logically equivalent. You instead have a problem with (P1 compatible with P2/P3). Is this your point ?

I am not sure you're being precise here, obviously a (proposition AND its negation) can't be consistent with ANYTHING.

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Answer me this, can she choose any other flavor than F and P2/P3 still be true?

Your question is the object of the entire argument. So yes, she can. To see why, you have to follow all the steps above, I admit that it's not clear that she can.

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I have a PS4 but want a PS5.

Am I doing this right?

I have a not-PS