(January 1, 2010 at 4:51 pm)Zhalentine Wrote: I don't think we did agree that (-1)(-1)= -1. Were you just trying to show that if (-1)(-1) = -1, then 0 = -2? You never mentioned you were doing that and when you said "For example, let's assume (-1)(-1) = +1." maybe you meant (-1)(-1) = -1.Yeah, corrected. Thanks for spotting the mistake!
Quote:Anyways, here is a math problem for youOh dear! Someone seems to be forgetting his constant!
"proof" that 0 = 1.
We compute the indefinite integral of (1/x dx) by parts. Set u = 1/x and
dv = dx, so that du = -1/x^2 dx and v = x.
We get:
indefinite integral of (1/x dx) = uv - indefinite integral of (v du)
= x/x + indefinite integral of (x/x^2 dx)
= 1 + indefinite integral of (1/x dx)
Subtracting indefinite integral of (1/x dx) from both sides, we get 0=1
You actually get:
0 = 1 - c, where c always equals 1.
Ergo you get: 0 = 1 - 1, which is correct
