RE: The nature of number
September 3, 2012 at 6:52 pm
(This post was last modified: September 3, 2012 at 6:59 pm by Categories+Sheaves.)
(September 3, 2012 at 10:47 am)jonb Wrote: Until we get on to CantorI mean, I don't really know what you mean by "generator of the series", or "fraction of the series". So nobody's getting disabused today. And yes, the type of stuff that can happen around a point is dictated by the 'bigger world' the point is stuck in. It's precisely this structure that allows us to do math
Ok I wish to add something. It is my contention that the number is not the generator of the series, but that the number is a fraction of the series. If I am wrong please disabuse me of this. Similarly I have also noticed that a point is afected by the field or dimention it is in.
(September 3, 2012 at 10:47 am)jonb Wrote: Any number of projections can be made from a point in two dimentional space and be equaly spaced around that point.Well, my first reaction is, of course you can do that in 3-space. Take the thing you made in 2-space, and imagine that's occurring within a plane in 3-space.
However in 3d:
Only specific numbers of projections can be made from a point in three dimensional space and be distributed equally around that point. Given this; it seems the structure of the field dictates the material within it, rather than the material creating the structure. Please help me through this.
But you overlooked this example for a very clear reason (or at least, my last paragraph was using a very different interpretation of 'regularly spaced'): all the examples of 'regularly spaced' points correspond to the vertices (or faces, if you're into poincare duality) of platonic solids (you're only missing the dodecahedron/icosahedron example, but I also can't see your second 3D example). If my memory serves me right, you have exactly three polytopes in each higher dimension (5+ iirc) and a whole bunch in dimension four (which is somehow the most interesting dimension for manifolds as well).
To prepare for geometric emergencies, I picked up a good book on polytopes/polyhedra (by Coxeter) a while back, so I guess I'll dig into it over the next week and see if I dredge up anything you might enjoy.
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But let's get this Cantor stuff done. EDIT: You should probably read the wikipedia proof first, my run-through is really sloppy/ugly/a PITA to read.
The shortest form of the argument I know is showing that there doesn't exist a 1-1 corresponding between the natural numbers, {1, 2, 3, 4, ...}, and the interval [0,1] (in the real numbers, which we'll express in their decimal expansions).
Suppose there does exist some function f that maps each natural number to each real number in [0,1], leaving none out. Then we can find a number in the following manner: the nth decimal place is '0' if f(n) is not zero, and the nth decimal place is '2' if f(n) = 0.
For the sake of making sure this map is well-defined: in cases where you have two ways of representing a decimal, like 1 = 0.999..., we pick the nth decimal place out of the representation that doesn't have the unending sequence of 9's (you could do it the other way too, but we have to be consistent). Call the number we generate in this way r.
In this way, we'll pick out a number such that there cannot exist some natural number n for which f(n)=r. If the nth decimal place of f(n)'s decimal expansion (sans infinite 9's) is zero, r will have a 2 in this same decimal place, and thus these numbers cannot be equal. If this nth decimal place is not zero, then the respective decimal place in r will be 0, followed by 0's and 2's (so there's no chance of some 999...'s sneaking in and messing things up).
Hence the notion that these two infinite sets, {1,2,3,...} and [0,1] are in some sense different: I cannot map {1,2,3...} to [0,1] in a way that hits every element of [0,1]. But I CAN map [0,1] to {1,2,3...} in a way that hits every natural number: map both 0 and 1 to 1, and for all other numbers, their decimal representation (sans 999...s, again, because we don't want to be ambiguous) has a 'first nonzero term', that must occur in some decimal place--be it the 1st, 2nd, 3rd... it must occur at the nth place for some natural number n--and then map said decimal to this n. For every natural number n, 10-n is a real number, so we'll cover all the natural numbers in this way.
So there is this asymmetry: [0,1] is 'big enough to fill' {1,2,3,...}, but the reverse relation isn't true. In this sense we can say one infinite set is bigger than another.
It should be clear that you can make a partial order relation on infinite sets in this way: If there exists some onto or surjective map f: A -> B, (that is to say, for every element b in B, there exists some a in A such that f(a)=b, i.e. all elements of b are 'hit by f', 'mapped to by f' or 'in the image of f') and no possible onto/surjective map in the opposite direction (some f-1: B -> A) then we can say A is 'bigger' than B. If we have the same situation that a surjective g: B -> C exists but a surjective h-1: C -> B does not, then the composition of f and g, creates a surjective map f(g()): A -> C so there is some transitivity: A > B and B > C yields A > C.
So I'm leaving out a lot, like,
-If you add the Axiom of Choice, this partial order relation becomes a strict order relation (everything is comparable)
-Expressing Cantor's diagonization argument in terms of powersets is more abstract but also the 'most natural' way of expressing the result. For instance, you don't have to fret over the fact that all nonzero terminating decimals also have a non-terminating (including a 999...) decimal expansion.
-Philosophical notes on how to interpret this result.
-Probably other stuff too
Anyway, now we have concrete stuff to discuss on the Cantor thing.