Solve this simple equation (help pls)

[SaStrike]

let me take a stab at failing at grade 8 maths. here you go, how to get 12

2 x (3x+2x) = 2 x (60)

10x = 120

x = 12

[GUBU]

3x + (2x)/2 = 60

I got 12.

Yes, I'm dumb. Help pls 😁

42

[Alex K]

At least I was close 😂

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😎
Well I multiplied both sides with 2 to get rid of the 1/2 😝

If you want to double both sides it is safe to multiply by two but did you multiply the 3x by 2 as well, or only part of that side?

3x + (2x)/2 = 60

1.5x + 2x = 120
3.5x = 120

x ≠ 12

but 

6x + 2x = 120
8x = 120
x = 15

Sorry I can't see how you'd get 12.  I must be rusty.

If e proceeded to remove the /2 only from that term and forgot the others and kept the 3x and 60, maybe?

[Whateverist]

If you want to double both sides it is safe to multiply by two but did you multiply the 3x by 2 as well, or only part of that side?

3x + (2x)/2 = 60

1.5x + 2x = 120
3.5x = 120

x ≠ 12

but 

6x + 2x = 120
8x = 120
x = 15

Sorry I can't see how you'd get 12.  I must be rusty.

If e proceeded to remove the /2 only from that term and forgot the others and kept the 3x and 60, maybe?

If he only removed the /2, left the 60 unchanged and then added the 3x to the 2x he would get 12.  Probably what he did.

[ErGingerbreadMandude]

Not exactly sure what I did tbh Lol
Hold up I'll post the problem see if you guys get 15 as well

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So this is the original problem I did some bla bla bla calculations and the answer I got(you guys got 😛) was 15

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See if you guys get 15 as well

[Alex K]

I don't understand the question. Is that Indian English??!

[Whateverist]

Not exactly sure what I did tbh Lol
Hold up I'll post the problem see if you guys get 15 as well

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So this is the original problem I did some bla bla bla calculations and the answer I got(you guys got 😛) was 15

---

See if you guys get 15 as well

Worker A completes the job at a rate of 1/20 of the job/day.  Worker B completes 1/30 of the job each day.  So you want to know how many (1/20 + 1/30) it will take to complete one job, assuming the two can work compatibly with no added or lost efficiency.  If you let x = the number of days needed to complete the job working together this way, then a better equation for the problem would be:

(1/20 + 1/30)x = 1

Since 1/20 + 1/30 = 50/600 which reduces to 1/12, you'd get 1/12 of the job done per day this way.  So your original answer of 12 days was correct.  But your original equation wouldn't get you there.

[Jackalope]

Here's how I solved it. (Keeping in mind my last math class was in 1984.)

3x + (2x)/2 = 60

2x/2 reduces to x, so 3x + x = 60

3x + x = 4x, so 4x = 60

4x/4 = 60/4

x = 15

[SaStrike]

The equation you posted and the picture you posted are different.

The equation is basic algebra x = 15
The picture word problem is rocket science though. I dont even know where to start.

[pocaracas]

Not exactly sure what I did tbh Lol
Hold up I'll post the problem see if you guys get 15 as well

---

So this is the original problem I did some bla bla bla calculations and the answer I got(you guys got 😛) was 15

---

See if you guys get 15 as well

Worker A completes the job at a rate of 1/20 of the job/day.  Worker B completes 1/30 of the job each day.  So you want to know how many (1/20 + 1/30) it will take to complete one job, assuming the two can work compatibly with no added or lost efficiency.  If you let x = the number of days needed to complete the job working together this way, then a better equation for the problem would be:

(1/20 + 1/30)x = 1

Since 1/20 + 1/30 = 50/600 which reduces to 1/12, you'd get 1/12 of the job done per day this way.  So your original answer of 12 days was correct.  But your original equation wouldn't get you there.

Maybe, but guy B only works for half the time. Guy A must pick up the other guy's slack!

1/20t +1/(30*2)t = 1

(1/20 + 1/60)t = 1
4/60 t = 1
t = 60/4 = 15