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Solve this simple equation (help pls)
#21
RE: Solve this simple equation (help pls)
(December 4, 2017 at 4:08 pm)Whateverist Wrote:
(December 4, 2017 at 12:16 pm)pool the matey Wrote: Not exactly sure what I did tbh Lol
Hold up I'll post the problem see if you guys get 15 as well

[Image: IMG_20171204_214654_2.jpg]

So this is the original problem I did some bla bla bla calculations and the answer I got(you guys got 😛) was 15

See if you guys get 15 as well


Worker A completes the job at a rate of 1/20 of the job/day.  Worker B completes 1/30 of the job each day.  So you want to know how many (1/20 + 1/30) it will take to complete one job, assuming the two can work compatibly with no added or lost efficiency.  If you let x = the number of days needed to complete the job working together this way, then a better equation for the problem would be:

(1/20 + 1/30)x = 1

Since 1/20 + 1/30 = 50/600 which reduces to 1/12, you'd get 1/12 of the job done per day this way.  So your original answer of 12 days was correct.  But your original equation wouldn't get you there.

OK, help me out here Mark. I get the 1/20 and 1/30 and 50/600. But isn't that if they both worked the same amount? A worked for a full unit of time, B worked for 1/2. Is you answer still correct?
I don't have an anger problem, I have an idiot problem.
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#22
RE: Solve this simple equation (help pls)
Yeah, mh brewer seems you got it. Answer is indeed 15 if it's 1/20 and 1/60
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#23
RE: Solve this simple equation (help pls)
Well that hardly feels right.
I don't have an anger problem, I have an idiot problem.
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#24
RE: Solve this simple equation (help pls)
My apologies.  My speculation for why the answer of 12 was obtained in the op was pointless.











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#25
RE: Solve this simple equation (help pls)
(December 4, 2017 at 7:07 pm)Kernel Sohcahtoa Wrote: My apologies.  My speculation for why the answer of 12 was obtained in the op was pointless.

GIGO. You (and the rest of us) didn't have the actual problem at hand, at first.
If you get to thinking you’re a person of some influence, try ordering somebody else’s dog around.
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#26
RE: Solve this simple equation (help pls)
(December 4, 2017 at 6:43 pm)pocaracas Wrote:
(December 4, 2017 at 4:08 pm)Whateverist Wrote: Worker A completes the job at a rate of 1/20 of the job/day.  Worker B completes 1/30 of the job each day.  So you want to know how many (1/20 + 1/30) it will take to complete one job, assuming the two can work compatibly with no added or lost efficiency.  If you let x = the number of days needed to complete the job working together this way, then a better equation for the problem would be:

(1/20 + 1/30)x = 1

Since 1/20 + 1/30 = 50/600 which reduces to 1/12, you'd get 1/12 of the job done per day this way.  So your original answer of 12 days was correct.  But your original equation wouldn't get you there.

Maybe, but guy B only works for half the time. Guy A must pick up the other guy's slack!

1/20t +1/(30*2)t = 1

(1/20 + 1/60)t = 1
4/60 t = 1
t = 60/4 = 15


My bad.  I only read as much as I thought I needed to.  Didn't get far.  That explains the other equation.  Thanks.

(December 4, 2017 at 6:45 pm)mh.brewer Wrote:
(December 4, 2017 at 4:08 pm)Whateverist Wrote: Worker A completes the job at a rate of 1/20 of the job/day.  Worker B completes 1/30 of the job each day.  So you want to know how many (1/20 + 1/30) it will take to complete one job, assuming the two can work compatibly with no added or lost efficiency.  If you let x = the number of days needed to complete the job working together this way, then a better equation for the problem would be:

(1/20 + 1/30)x = 1

Since 1/20 + 1/30 = 50/600 which reduces to 1/12, you'd get 1/12 of the job done per day this way.  So your original answer of 12 days was correct.  But your original equation wouldn't get you there.

OK, help me out here Mark. I get the 1/20 and 1/30 and 50/600. But isn't that if they both worked the same amount? A worked for a full unit of time, B worked for 1/2. Is you answer still correct?


You are right.  I didn't bother reading the whole thing.  I completely missed the part about the one guy only working half as much.
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#27
RE: Solve this simple equation (help pls)
(December 4, 2017 at 3:57 pm)Alex K Wrote: I don't understand the question. Is that Indian English??!

🤣 pretty much





this is our airbag

[Image: images?q=tbn:ANd9GcRqXwie8txioUIGxhvoSS0...NMK-MP9C3Q]

in case of emergency suffocate yourself with the bag instead of a long painful death 😂
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#28
RE: Solve this simple equation (help pls)
Got a new one see if you guys get it

[Image: IMG_20171206_192403_2.jpg]
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#29
RE: Solve this simple equation (help pls)
Girl on stage ---> mother ---> brother (girl's uncle) ---> father (girl's grandfather) <-- mother (girl's mother or aunt?) <--- Gourav (girl's brother or cousin)
Her mother is Gourav's mother or aunt... I don't know.... it's unclear.

Considering the way the thing is phrased.... I'd say someone is illegitimate...
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#30
RE: Solve this simple equation (help pls)
(December 6, 2017 at 12:42 pm)pocaracas Wrote: Girl on stage ---> mother ---> brother (girl's uncle) ---> father (girl's grandfather) <-- mother (girl's mother or aunt?) <--- Gourav (girl's brother or cousin)
Her mother is Gourav's mother or aunt... I don't know.... it's unclear.

Considering the way the thing is phrased.... I'd say someone is illegitimate...

Good try but there is a correct answer (it's not a trick question, you just have to think about it)
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