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Applicability of Maths to the Universe
#71
RE: Applicability of Maths to the Universe
If we're speaking of intuition, a person might wonder why platonists allowed intuitions based on mental and physical objects to inform them both that there were platonic abstracts, and what they might be like. Still, given room to alter it's semantics, as room has been given to other metaphysical notions like materialism, it's conceivable that it might better describe some observed x in reality. It's simply becoming difficult to envision what that x might be as we learn more, as our ability to observe grows, and...ofc, as the semantics for other positions which make antithetical claims box it out.

Gods, minds, and numbers was a poor choice of field, in retrospect. Gods because they don't exist. Minds because they're meat. Numbers because..well...fuckin numbers, I'll leave that to you.
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#72
RE: Applicability of Maths to the Universe
polymath, can you tell me if there is any issue with this answer?

Quote:Why is this number equal to 3.14159....? Why is it not some other (ir)rational number?

Answer is that with the usual Euclidean metric that is the number that one gets, the value of π is dependent on the geometry that is being used, so on a sphere the π used to obtain the area will be different.

Another question to ask is that if S=π(sub1)r^2 is the area of the circle and C=π(sub2)2r is the circumference why π(sub1)=π(sub2)=π ? What geometries or metrics will result in π(sub1)≠π(sub2) ?

From:
https://math.stackexchange.com/questions...to-3-14159


If no issues, then this is generally the answer that satisfies my question. Even if pi was definitely a normal number, I still would've asked this question.
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#73
RE: Applicability of Maths to the Universe
(June 17, 2020 at 12:08 pm)Grandizer Wrote: polymath, can you tell me if there is any issue with this answer?

Quote:Why is this number equal to 3.14159....? Why is it not some other (ir)rational number?

Answer is that with the usual Euclidean metric that is the number that one gets, the value of π is dependent on the geometry that is being used, so on a sphere the π used to obtain the area will be different.

Another question to ask is that if S=π(sub1)r^2 is the area of the circle and C=π(sub2)2r is the circumference why π(sub1)=π(sub2)=π ? What geometries or metrics will result in π(sub1)≠π(sub2) ?

From:
https://math.stackexchange.com/questions...to-3-14159


If no issues, then this is generally the answer that satisfies my question. Even if pi was definitely a normal number, I still would've asked this question.

On a sphere, the ratio between radius and area (or circumference) of a circle is not a constant at all. For example, if you are at the north pole, the equator is a 'circle' whose circumference is 4 times the radius (not 2pi). But, the limit as the radius goes to 0 will give you pi back. Similarly for the area.

We choose circles because we have a distance function making R^2 into an inner product space, leading to the Pythagorean metric. If you use a 'taxicab' metric, the ratio would be 4sqrt(2) for the circumference and 2 for the area.

Or, you could live on a cone. At the vertex, you would have a constant ratio of radius to circumference (and for that matter between area and the square of the radius) and the ratio would depend on the opening angle of the cone, but at other points it would be the usual value of pi (if you measure distance in the cone).
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