RE: Can you cut a cake fairly to solve this middle school math problem?22nd September 2016, 14:30
(14th August 2016, 15:57)mh.brewer Wrote:(14th August 2016, 12:50)Whateverist Wrote: Exactamundo. But to elaborate
Of course every one of the triangles have the same height regardless of where their base may be. For those which straddle a corner, each can be dissected into two triangles with a common height whose bases sum to the same as the other. So for a square with side length = 20, the base of each triangle must be 4(20)/5 = 16 and the combined sides of a piece which includes a corner, like your red one, where 12 + 4 = 16. Since the height of both triangles remains 8, the combined area of the two triangles would be 12(8)/2 + 4(8)/2 which can be rewritten as (12 + 8)(8)/2.
If that's what Losty has to do, none of you are getting equal portions of cake. Apologies Losty.
Mathing is a sin anyway so I'm not offended. I figured we'd find something more fun to do than cutting a cake