the bastards !!!

Giving up. I have been trying to understand my math homework all night. Guess I'm going to have to go to the tutoring center tomorrow.

(February 13, 2018 at 5:57 am)Martian Mermaid Wrote: Giving up. I have been trying to understand my math homework all night. Guess I'm going to have to go to the tutoring center tomorrow.

Or you can try us!

(February 13, 2018 at 6:50 am)pocaracas Wrote:

(February 13, 2018 at 5:57 am)Martian Mermaid Wrote: Giving up. I have been trying to understand my math homework all night. Guess I'm going to have to go to the tutoring center tomorrow.

Or you can try us!

Can't hurt to try xD 

Okay I need to find the domain of f(x)=(x+1)/(x+2). 
If there is some chance you know how to do that, please tell me how lol.

The second day at work after the leave.. and I'm trying to find a balance.. it's so difficult :
ooo math, how nice...i know cool website about discrete math... wait a moment ..

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(February 13, 2018 at 6:55 am)Martian Mermaid Wrote: Can't hurt to try xD 

Okay I need to find the domain of f(x)=(x+1)/(x+2). 
If there is some chance you know how to do that, please tell me how lol.

ok... i'm not good enough in math or maybe rather i'm not good to explain..
i think they are better here than me
but this is a website which i like it and you can use it if you want you can use it..

https://math.stackexchange.com/questions...a-function

(February 13, 2018 at 6:55 am)Martian Mermaid Wrote:

(February 13, 2018 at 6:50 am)pocaracas Wrote: Or you can try us!

Can't hurt to try xD 

Okay I need to find the domain of f(x)=(x+1)/(x+2). 
If there is some chance you know how to do that, please tell me how lol.

So... on first look, you have a function of X, so let's start with the whole Real domain and see where things break.

Things should break when you divide by zero (but the numerator, on top, is not zero), so that the result is not determined (what we usually call infinity).

The guy on bottom is zero when x+2=0, or when x = -2.

That makes f(2) = (-2+1)/(-2+2) = -1/0, which checks out as an invalid point, where f(x) loses meaning.
Any other?..... doesn't look like it, so.... your domain is simply ℝ, except {-2}, or ]-∞ , -2[ ∪ ]-2, +∞[

Math sucks. Hate it.

(February 13, 2018 at 9:11 am)pocaracas Wrote:

(February 13, 2018 at 6:55 am)Martian Mermaid Wrote: Can't hurt to try xD 

Okay I need to find the domain of f(x)=(x+1)/(x+2). 
If there is some chance you know how to do that, please tell me how lol.

So... on first look, you have a function of X, so let's start with the whole Real domain and see where things break.

Things should break when you divide by zero (but the numerator, on top, is not zero), so that the result is not determined (what we usually call infinity).

The guy on bottom is zero when x+2=0, or when x = -2.

That makes f(2) = (-2+1)/(-2+2) = -1/0, which checks out as an invalid point, where f(x) loses meaning.
Any other?..... doesn't look like it, so.... your domain is simply ℝ, except {-2}, or ]-∞ , -2[ ∪ ]-2, +∞[

Yeah, that makes sense, thanks.

(February 13, 2018 at 8:39 pm)Martian Mermaid Wrote:

(February 13, 2018 at 9:11 am)pocaracas Wrote: So... on first look, you have a function of X, so let's start with the whole Real domain and see where things break.

Things should break when you divide by zero (but the numerator, on top, is not zero), so that the result is not determined (what we usually call infinity).

The guy on bottom is zero when x+2=0, or when x = -2.

That makes f(2) = (-2+1)/(-2+2) = -1/0, which checks out as an invalid point, where f(x) loses meaning.
Any other?..... doesn't look like it, so.... your domain is simply ℝ, except {-2}, or ]-∞ , -2[ ∪ ]-2, +∞[

Yeah, that makes sense,  thanks.

That makes sense?

I can find my way through the cardiovascular system, almost with my eyes shut (you have to sleep sometime.  Why not during surgery?), but maths just makes my head hurt.

Catching up on the www. Very jet lagged, but OK.